3.6.96 \(\int \frac {1}{x^4 (c+a^2 c x^2)^{5/2} \arctan (a x)^2} \, dx\) [596]

3.6.96.1 Optimal result

Integrand size = 24, antiderivative size = 24 \[ \int \frac {1}{x^4 \left (c+a^2 c x^2\right )^{5/2} \arctan (a x)^2} \, dx=-\frac {a^3}{c \left (c+a^2 c x^2\right )^{3/2} \arctan (a x)}-\frac {2 a^3}{c^2 \sqrt {c+a^2 c x^2} \arctan (a x)}-\frac {11 a^3 \sqrt {1+a^2 x^2} \text {Si}(\arctan (a x))}{4 c^2 \sqrt {c+a^2 c x^2}}-\frac {3 a^3 \sqrt {1+a^2 x^2} \text {Si}(3 \arctan (a x))}{4 c^2 \sqrt {c+a^2 c x^2}}+\frac {\text {Int}\left (\frac {1}{x^4 \sqrt {c+a^2 c x^2} \arctan (a x)^2},x\right )}{c^2}-\frac {2 a^2 \text {Int}\left (\frac {1}{x^2 \sqrt {c+a^2 c x^2} \arctan (a x)^2},x\right )}{c^2} \]

output

-a^3/c/(a^2*c*x^2+c)^(3/2)/arctan(a*x)-2*a^3/c^2/arctan(a*x)/(a^2*c*x^2+c) 
^(1/2)-11/4*a^3*Si(arctan(a*x))*(a^2*x^2+1)^(1/2)/c^2/(a^2*c*x^2+c)^(1/2)- 
3/4*a^3*Si(3*arctan(a*x))*(a^2*x^2+1)^(1/2)/c^2/(a^2*c*x^2+c)^(1/2)+Uninte 
grable(1/x^4/arctan(a*x)^2/(a^2*c*x^2+c)^(1/2),x)/c^2-2*a^2*Unintegrable(1 
/x^2/arctan(a*x)^2/(a^2*c*x^2+c)^(1/2),x)/c^2
 

3.6.96.2 Mathematica [N/A]

Not integrable

Time = 7.73 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.08 \[ \int \frac {1}{x^4 \left (c+a^2 c x^2\right )^{5/2} \arctan (a x)^2} \, dx=\int \frac {1}{x^4 \left (c+a^2 c x^2\right )^{5/2} \arctan (a x)^2} \, dx \]

input

Integrate[1/(x^4*(c + a^2*c*x^2)^(5/2)*ArcTan[a*x]^2),x]
 

output

Integrate[1/(x^4*(c + a^2*c*x^2)^(5/2)*ArcTan[a*x]^2), x]
 

3.6.96.3 Rubi [N/A]

Not integrable

Time = 4.69 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.00, number of steps used = 13, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {5501, 5501, 5437, 5501, 5437, 5506, 5505, 3042, 3780, 4906, 2009, 5560}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {1}{x^4 \arctan (a x)^2 \left (a^2 c x^2+c\right )^{5/2}} \, dx\)

\(\Big \downarrow \) 5501

\(\displaystyle \frac {\int \frac {1}{x^4 \left (a^2 c x^2+c\right )^{3/2} \arctan (a x)^2}dx}{c}-a^2 \int \frac {1}{x^2 \left (a^2 c x^2+c\right )^{5/2} \arctan (a x)^2}dx\)

\(\Big \downarrow \) 5501

\(\displaystyle \frac {\frac {\int \frac {1}{x^4 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \int \frac {1}{x^2 \left (a^2 c x^2+c\right )^{3/2} \arctan (a x)^2}dx}{c}-a^2 \left (\frac {\int \frac {1}{x^2 \left (a^2 c x^2+c\right )^{3/2} \arctan (a x)^2}dx}{c}-a^2 \int \frac {1}{\left (a^2 c x^2+c\right )^{5/2} \arctan (a x)^2}dx\right )\)

\(\Big \downarrow \) 5437

\(\displaystyle \frac {\frac {\int \frac {1}{x^4 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \int \frac {1}{x^2 \left (a^2 c x^2+c\right )^{3/2} \arctan (a x)^2}dx}{c}-a^2 \left (\frac {\int \frac {1}{x^2 \left (a^2 c x^2+c\right )^{3/2} \arctan (a x)^2}dx}{c}-a^2 \left (-3 a \int \frac {x}{\left (a^2 c x^2+c\right )^{5/2} \arctan (a x)}dx-\frac {1}{a c \arctan (a x) \left (a^2 c x^2+c\right )^{3/2}}\right )\right )\)

\(\Big \downarrow \) 5501

\(\displaystyle \frac {\frac {\int \frac {1}{x^4 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (\frac {\int \frac {1}{x^2 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \int \frac {1}{\left (a^2 c x^2+c\right )^{3/2} \arctan (a x)^2}dx\right )}{c}-a^2 \left (\frac {\frac {\int \frac {1}{x^2 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \int \frac {1}{\left (a^2 c x^2+c\right )^{3/2} \arctan (a x)^2}dx}{c}-a^2 \left (-3 a \int \frac {x}{\left (a^2 c x^2+c\right )^{5/2} \arctan (a x)}dx-\frac {1}{a c \arctan (a x) \left (a^2 c x^2+c\right )^{3/2}}\right )\right )\)

\(\Big \downarrow \) 5437

\(\displaystyle \frac {\frac {\int \frac {1}{x^4 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (\frac {\int \frac {1}{x^2 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (-a \int \frac {x}{\left (a^2 c x^2+c\right )^{3/2} \arctan (a x)}dx-\frac {1}{a c \arctan (a x) \sqrt {a^2 c x^2+c}}\right )\right )}{c}-a^2 \left (\frac {\frac {\int \frac {1}{x^2 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (-a \int \frac {x}{\left (a^2 c x^2+c\right )^{3/2} \arctan (a x)}dx-\frac {1}{a c \arctan (a x) \sqrt {a^2 c x^2+c}}\right )}{c}-a^2 \left (-3 a \int \frac {x}{\left (a^2 c x^2+c\right )^{5/2} \arctan (a x)}dx-\frac {1}{a c \arctan (a x) \left (a^2 c x^2+c\right )^{3/2}}\right )\right )\)

\(\Big \downarrow \) 5506

\(\displaystyle \frac {\frac {\int \frac {1}{x^4 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (\frac {\int \frac {1}{x^2 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (-\frac {a \sqrt {a^2 x^2+1} \int \frac {x}{\left (a^2 x^2+1\right )^{3/2} \arctan (a x)}dx}{c \sqrt {a^2 c x^2+c}}-\frac {1}{a c \arctan (a x) \sqrt {a^2 c x^2+c}}\right )\right )}{c}-a^2 \left (\frac {\frac {\int \frac {1}{x^2 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (-\frac {a \sqrt {a^2 x^2+1} \int \frac {x}{\left (a^2 x^2+1\right )^{3/2} \arctan (a x)}dx}{c \sqrt {a^2 c x^2+c}}-\frac {1}{a c \arctan (a x) \sqrt {a^2 c x^2+c}}\right )}{c}-a^2 \left (-\frac {3 a \sqrt {a^2 x^2+1} \int \frac {x}{\left (a^2 x^2+1\right )^{5/2} \arctan (a x)}dx}{c^2 \sqrt {a^2 c x^2+c}}-\frac {1}{a c \arctan (a x) \left (a^2 c x^2+c\right )^{3/2}}\right )\right )\)

\(\Big \downarrow \) 5505

\(\displaystyle \frac {\frac {\int \frac {1}{x^4 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (\frac {\int \frac {1}{x^2 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (-\frac {\sqrt {a^2 x^2+1} \int \frac {a x}{\sqrt {a^2 x^2+1} \arctan (a x)}d\arctan (a x)}{a c \sqrt {a^2 c x^2+c}}-\frac {1}{a c \arctan (a x) \sqrt {a^2 c x^2+c}}\right )\right )}{c}-a^2 \left (\frac {\frac {\int \frac {1}{x^2 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (-\frac {\sqrt {a^2 x^2+1} \int \frac {a x}{\sqrt {a^2 x^2+1} \arctan (a x)}d\arctan (a x)}{a c \sqrt {a^2 c x^2+c}}-\frac {1}{a c \arctan (a x) \sqrt {a^2 c x^2+c}}\right )}{c}-a^2 \left (-\frac {3 \sqrt {a^2 x^2+1} \int \frac {a x}{\left (a^2 x^2+1\right )^{3/2} \arctan (a x)}d\arctan (a x)}{a c^2 \sqrt {a^2 c x^2+c}}-\frac {1}{a c \arctan (a x) \left (a^2 c x^2+c\right )^{3/2}}\right )\right )\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\int \frac {1}{x^4 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (\frac {\int \frac {1}{x^2 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (-\frac {\sqrt {a^2 x^2+1} \int \frac {\sin (\arctan (a x))}{\arctan (a x)}d\arctan (a x)}{a c \sqrt {a^2 c x^2+c}}-\frac {1}{a c \arctan (a x) \sqrt {a^2 c x^2+c}}\right )\right )}{c}-a^2 \left (\frac {\frac {\int \frac {1}{x^2 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (-\frac {\sqrt {a^2 x^2+1} \int \frac {\sin (\arctan (a x))}{\arctan (a x)}d\arctan (a x)}{a c \sqrt {a^2 c x^2+c}}-\frac {1}{a c \arctan (a x) \sqrt {a^2 c x^2+c}}\right )}{c}-a^2 \left (-\frac {3 \sqrt {a^2 x^2+1} \int \frac {a x}{\left (a^2 x^2+1\right )^{3/2} \arctan (a x)}d\arctan (a x)}{a c^2 \sqrt {a^2 c x^2+c}}-\frac {1}{a c \arctan (a x) \left (a^2 c x^2+c\right )^{3/2}}\right )\right )\)

\(\Big \downarrow \) 3780

\(\displaystyle \frac {\frac {\int \frac {1}{x^4 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (\frac {\int \frac {1}{x^2 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (-\frac {\sqrt {a^2 x^2+1} \text {Si}(\arctan (a x))}{a c \sqrt {a^2 c x^2+c}}-\frac {1}{a c \arctan (a x) \sqrt {a^2 c x^2+c}}\right )\right )}{c}-a^2 \left (\frac {\frac {\int \frac {1}{x^2 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (-\frac {\sqrt {a^2 x^2+1} \text {Si}(\arctan (a x))}{a c \sqrt {a^2 c x^2+c}}-\frac {1}{a c \arctan (a x) \sqrt {a^2 c x^2+c}}\right )}{c}-a^2 \left (-\frac {3 \sqrt {a^2 x^2+1} \int \frac {a x}{\left (a^2 x^2+1\right )^{3/2} \arctan (a x)}d\arctan (a x)}{a c^2 \sqrt {a^2 c x^2+c}}-\frac {1}{a c \arctan (a x) \left (a^2 c x^2+c\right )^{3/2}}\right )\right )\)

\(\Big \downarrow \) 4906

\(\displaystyle \frac {\frac {\int \frac {1}{x^4 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (\frac {\int \frac {1}{x^2 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (-\frac {\sqrt {a^2 x^2+1} \text {Si}(\arctan (a x))}{a c \sqrt {a^2 c x^2+c}}-\frac {1}{a c \arctan (a x) \sqrt {a^2 c x^2+c}}\right )\right )}{c}-a^2 \left (\frac {\frac {\int \frac {1}{x^2 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (-\frac {\sqrt {a^2 x^2+1} \text {Si}(\arctan (a x))}{a c \sqrt {a^2 c x^2+c}}-\frac {1}{a c \arctan (a x) \sqrt {a^2 c x^2+c}}\right )}{c}-a^2 \left (-\frac {3 \sqrt {a^2 x^2+1} \int \left (\frac {a x}{4 \sqrt {a^2 x^2+1} \arctan (a x)}+\frac {\sin (3 \arctan (a x))}{4 \arctan (a x)}\right )d\arctan (a x)}{a c^2 \sqrt {a^2 c x^2+c}}-\frac {1}{a c \arctan (a x) \left (a^2 c x^2+c\right )^{3/2}}\right )\right )\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {\frac {\int \frac {1}{x^4 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (\frac {\int \frac {1}{x^2 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (-\frac {\sqrt {a^2 x^2+1} \text {Si}(\arctan (a x))}{a c \sqrt {a^2 c x^2+c}}-\frac {1}{a c \arctan (a x) \sqrt {a^2 c x^2+c}}\right )\right )}{c}-a^2 \left (\frac {\frac {\int \frac {1}{x^2 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (-\frac {\sqrt {a^2 x^2+1} \text {Si}(\arctan (a x))}{a c \sqrt {a^2 c x^2+c}}-\frac {1}{a c \arctan (a x) \sqrt {a^2 c x^2+c}}\right )}{c}-a^2 \left (-\frac {3 \sqrt {a^2 x^2+1} \left (\frac {1}{4} \text {Si}(\arctan (a x))+\frac {1}{4} \text {Si}(3 \arctan (a x))\right )}{a c^2 \sqrt {a^2 c x^2+c}}-\frac {1}{a c \arctan (a x) \left (a^2 c x^2+c\right )^{3/2}}\right )\right )\)

\(\Big \downarrow \) 5560

\(\displaystyle \frac {\frac {\int \frac {1}{x^4 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (\frac {\int \frac {1}{x^2 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (-\frac {\sqrt {a^2 x^2+1} \text {Si}(\arctan (a x))}{a c \sqrt {a^2 c x^2+c}}-\frac {1}{a c \arctan (a x) \sqrt {a^2 c x^2+c}}\right )\right )}{c}-a^2 \left (\frac {\frac {\int \frac {1}{x^2 \sqrt {a^2 c x^2+c} \arctan (a x)^2}dx}{c}-a^2 \left (-\frac {\sqrt {a^2 x^2+1} \text {Si}(\arctan (a x))}{a c \sqrt {a^2 c x^2+c}}-\frac {1}{a c \arctan (a x) \sqrt {a^2 c x^2+c}}\right )}{c}-a^2 \left (-\frac {3 \sqrt {a^2 x^2+1} \left (\frac {1}{4} \text {Si}(\arctan (a x))+\frac {1}{4} \text {Si}(3 \arctan (a x))\right )}{a c^2 \sqrt {a^2 c x^2+c}}-\frac {1}{a c \arctan (a x) \left (a^2 c x^2+c\right )^{3/2}}\right )\right )\)

input

Int[1/(x^4*(c + a^2*c*x^2)^(5/2)*ArcTan[a*x]^2),x]
 

output

$Aborted
 

3.6.96.3.1 Defintions of rubi rules used

rule 2009

Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 3042

Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3780

Int[sin[(e_.) + (f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[SinInte 
gral[e + f*x]/d, x] /; FreeQ[{c, d, e, f}, x] && EqQ[d*e - c*f, 0]
 

rule 4906

Int[Cos[(a_.) + (b_.)*(x_)]^(p_.)*((c_.) + (d_.)*(x_))^(m_.)*Sin[(a_.) + (b 
_.)*(x_)]^(n_.), x_Symbol] :> Int[ExpandTrigReduce[(c + d*x)^m, Sin[a + b*x 
]^n*Cos[a + b*x]^p, x], x] /; FreeQ[{a, b, c, d, m}, x] && IGtQ[n, 0] && IG 
tQ[p, 0]
 

rule 5437

Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_)*((d_) + (e_.)*(x_)^2)^(q_), x_S 
ymbol] :> Simp[(d + e*x^2)^(q + 1)*((a + b*ArcTan[c*x])^(p + 1)/(b*c*d*(p + 
 1))), x] - Simp[2*c*((q + 1)/(b*(p + 1)))   Int[x*(d + e*x^2)^q*(a + b*Arc 
Tan[c*x])^(p + 1), x], x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[e, c^2*d] && 
LtQ[q, -1] && LtQ[p, -1]
 

rule 5501

Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)*(x_)^(m_)*((d_) + (e_.)*(x_)^2 
)^(q_), x_Symbol] :> Simp[1/d   Int[x^m*(d + e*x^2)^(q + 1)*(a + b*ArcTan[c 
*x])^p, x], x] - Simp[e/d   Int[x^(m + 2)*(d + e*x^2)^q*(a + b*ArcTan[c*x]) 
^p, x], x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[e, c^2*d] && IntegersQ[p, 2* 
q] && LtQ[q, -1] && ILtQ[m, 0] && NeQ[p, -1]
 

rule 5505

Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)*(x_)^(m_.)*((d_) + (e_.)*(x_)^ 
2)^(q_), x_Symbol] :> Simp[d^q/c^(m + 1)   Subst[Int[(a + b*x)^p*(Sin[x]^m/ 
Cos[x]^(m + 2*(q + 1))), x], x, ArcTan[c*x]], x] /; FreeQ[{a, b, c, d, e, p 
}, x] && EqQ[e, c^2*d] && IGtQ[m, 0] && ILtQ[m + 2*q + 1, 0] && (IntegerQ[q 
] || GtQ[d, 0])
 

rule 5506

Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)*(x_)^(m_.)*((d_) + (e_.)*(x_)^ 
2)^(q_), x_Symbol] :> Simp[d^(q + 1/2)*(Sqrt[1 + c^2*x^2]/Sqrt[d + e*x^2]) 
  Int[x^m*(1 + c^2*x^2)^q*(a + b*ArcTan[c*x])^p, x], x] /; FreeQ[{a, b, c, 
d, e, p}, x] && EqQ[e, c^2*d] && IGtQ[m, 0] && ILtQ[m + 2*q + 1, 0] &&  !(I 
ntegerQ[q] || GtQ[d, 0])
 

rule 5560

Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)*(u_.), x_Symbol] :> Unintegrab 
le[u*(a + b*ArcTan[c*x])^p, x] /; FreeQ[{a, b, c, p}, x] && (EqQ[u, 1] || M 
atchQ[u, ((d_.) + (e_.)*x)^(q_.) /; FreeQ[{d, e, q}, x]] || MatchQ[u, ((f_. 
)*x)^(m_.)*((d_.) + (e_.)*x)^(q_.) /; FreeQ[{d, e, f, m, q}, x]] || MatchQ[ 
u, ((d_.) + (e_.)*x^2)^(q_.) /; FreeQ[{d, e, q}, x]] || MatchQ[u, ((f_.)*x) 
^(m_.)*((d_.) + (e_.)*x^2)^(q_.) /; FreeQ[{d, e, f, m, q}, x]])
 

3.6.96.4 Maple [N/A] (verified)

Not integrable

Time = 33.28 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.92

\[\int \frac {1}{x^{4} \left (a^{2} c \,x^{2}+c \right )^{\frac {5}{2}} \arctan \left (a x \right )^{2}}d x\]

input

int(1/x^4/(a^2*c*x^2+c)^(5/2)/arctan(a*x)^2,x)
 

output

int(1/x^4/(a^2*c*x^2+c)^(5/2)/arctan(a*x)^2,x)
 

3.6.96.5 Fricas [N/A]

Not integrable

Time = 0.24 (sec) , antiderivative size = 63, normalized size of antiderivative = 2.62 \[ \int \frac {1}{x^4 \left (c+a^2 c x^2\right )^{5/2} \arctan (a x)^2} \, dx=\int { \frac {1}{{\left (a^{2} c x^{2} + c\right )}^{\frac {5}{2}} x^{4} \arctan \left (a x\right )^{2}} \,d x } \]

input

integrate(1/x^4/(a^2*c*x^2+c)^(5/2)/arctan(a*x)^2,x, algorithm="fricas")
 

output

integral(sqrt(a^2*c*x^2 + c)/((a^6*c^3*x^10 + 3*a^4*c^3*x^8 + 3*a^2*c^3*x^ 
6 + c^3*x^4)*arctan(a*x)^2), x)
 

3.6.96.6 Sympy [N/A]

Not integrable

Time = 31.37 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.08 \[ \int \frac {1}{x^4 \left (c+a^2 c x^2\right )^{5/2} \arctan (a x)^2} \, dx=\int \frac {1}{x^{4} \left (c \left (a^{2} x^{2} + 1\right )\right )^{\frac {5}{2}} \operatorname {atan}^{2}{\left (a x \right )}}\, dx \]

input

integrate(1/x**4/(a**2*c*x**2+c)**(5/2)/atan(a*x)**2,x)
 

output

Integral(1/(x**4*(c*(a**2*x**2 + 1))**(5/2)*atan(a*x)**2), x)
 

3.6.96.7 Maxima [N/A]

Not integrable

Time = 0.41 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.00 \[ \int \frac {1}{x^4 \left (c+a^2 c x^2\right )^{5/2} \arctan (a x)^2} \, dx=\int { \frac {1}{{\left (a^{2} c x^{2} + c\right )}^{\frac {5}{2}} x^{4} \arctan \left (a x\right )^{2}} \,d x } \]

input

integrate(1/x^4/(a^2*c*x^2+c)^(5/2)/arctan(a*x)^2,x, algorithm="maxima")
 

output

integrate(1/((a^2*c*x^2 + c)^(5/2)*x^4*arctan(a*x)^2), x)
 

3.6.96.8 Giac [N/A]

Not integrable

Time = 126.88 (sec) , antiderivative size = 3, normalized size of antiderivative = 0.12 \[ \int \frac {1}{x^4 \left (c+a^2 c x^2\right )^{5/2} \arctan (a x)^2} \, dx=\int { \frac {1}{{\left (a^{2} c x^{2} + c\right )}^{\frac {5}{2}} x^{4} \arctan \left (a x\right )^{2}} \,d x } \]

input

integrate(1/x^4/(a^2*c*x^2+c)^(5/2)/arctan(a*x)^2,x, algorithm="giac")
 

output

sage0*x
 

3.6.96.9 Mupad [N/A]

Not integrable

Time = 0.50 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.00 \[ \int \frac {1}{x^4 \left (c+a^2 c x^2\right )^{5/2} \arctan (a x)^2} \, dx=\int \frac {1}{x^4\,{\mathrm {atan}\left (a\,x\right )}^2\,{\left (c\,a^2\,x^2+c\right )}^{5/2}} \,d x \]

input

int(1/(x^4*atan(a*x)^2*(c + a^2*c*x^2)^(5/2)),x)
 

output

int(1/(x^4*atan(a*x)^2*(c + a^2*c*x^2)^(5/2)), x)